scheelings
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When the chemistry is more accurate? (assuming all sugar is fermented)
For those that like Chemistry:
C12H22O11 + H2O + invertase => 2 C6H12O6
C6H12O6 + Zymase => 2 C2H5OH + 2 CO2
So 1 mol of sucrose yields 4 mols of ethanol.
Molar mass of sucrose = 342.30 g/mol (based on molecular weight)
Molar mass of ethanol = 46.06844 g/mol
Therefore 342.3g of sucrose, yields 184.273 g of ethanol
Or more conveniently, every 100g of sugar, yields 53.8g of ethanol
The density of ethanol is 0.789 g/cm³
1L ethanol = 0.789*1 => 0.789KG
Therefore 53.8g of ethanol = 68.23 millilitres of ethanol
This volume can be assumed to be produced for every 100g of sugar added as long as the alcohol threshold remains below the theoretical upper limit of the yeast.
For those that don't:
So every 1kg of sugar added to a 30 litre brew, increase the alcoholic content by 2.22%.
For those that like Chemistry:
C12H22O11 + H2O + invertase => 2 C6H12O6
C6H12O6 + Zymase => 2 C2H5OH + 2 CO2
So 1 mol of sucrose yields 4 mols of ethanol.
Molar mass of sucrose = 342.30 g/mol (based on molecular weight)
Molar mass of ethanol = 46.06844 g/mol
Therefore 342.3g of sucrose, yields 184.273 g of ethanol
Or more conveniently, every 100g of sugar, yields 53.8g of ethanol
The density of ethanol is 0.789 g/cm³
1L ethanol = 0.789*1 => 0.789KG
Therefore 53.8g of ethanol = 68.23 millilitres of ethanol
This volume can be assumed to be produced for every 100g of sugar added as long as the alcohol threshold remains below the theoretical upper limit of the yeast.
For those that don't:
So every 1kg of sugar added to a 30 litre brew, increase the alcoholic content by 2.22%.