peebee
Out of Control
There's a not very good table on https://en.wikipedia.org/wiki/Hard_water: If you can battle with the "not very good" you can determine your "Clark°" measure divided by 0.7016 is Harness in French°. Why do that? French° x10 is mg/L "as CaCO3". Oh glory, glory, ... so, you've got 22.07/0.7016x10 = 314.57mg/L "as CaCO3". Still not very useful, but if you multiply by 0.4 you get the amount of Calcium ... 125.83mg/L ... but my favourite way is divide by 50 (nice round number) to get mEq/L ... 6.29mEq/L of Calcium. Only need a magic number to apply to that (rummage, rummage ... ah, here we go ...) 20.039x6.29 = 126.05mg/L of Calcium.My water from Severn Trent is stated as “very hard” Clark 22.07 whato that is, and the ph is an average of 7.41 so would that be classed as high alkalinity?
There's a bit of a problem, that Calcium number contains your Magnesium masquerading as Calcium. Sorry, that's just the way of "Hardness". And "Alkalinity", it will be all "bicarbonate" at pH 7.41, but you haven't provided enough information to extract that yet.
Tell you what. Take all those really simple sums to @MashBag and ask him what he thinks ... (He said, what? ... He did, WHAT! ... well I'm not putting me hand in there to get them out again.) ... Fortunately!
... You don't need all that "Hardness" codswallop, so no loss! ... Unfortunately! Severn Trent tie up information you do need in all that "Hardness" twaddle, but you're in luck ... I happen to know someone who wrote a spreadsheet to extract the good stuff from this pile of poo. Yeah, it's my "Defuddler"! Link below in my signature. Get the "development" version, haven't tested it in Google Sheets (free) or LibreOffice Calc (free) yet but it was developed in Microsoft Excel 365 and should work in any of them.
[EDIT: Silly me, I multiplied by 0.7016 instead of divided ... corrected! Now 126.05mg/L Ca ... that's "hard"!]
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