The basic formula for dilution is Conc1 X Vol1 = Conc2 X Vol2
The volumes are what you obtain, not what you need to add.
Say that you start from 75% and want to obtain 250 mL of 25%. Then the equation becomes:
75% X vol1 = 25% X 250
Solving this gives: vol1 = 25% X 250 / 75% = 83 mL of the 75% solution.
Add this in the bottle, then add (250 - 83) mL distilled/RO/demineralised water, 167 mL. Then you have 250 mL of a 25% phosphoric acid solution.
I hate to inform you of this, but your equation is totally invalid. The real dilution equivalence is:
Molarity1 x Vol1 = Molarity2 x Vol2 (or Normality1 x Vol1 = Normality2 x Vol2)
It only takes 60.49 mL of 75% Phosphoric Acid to make 250 mL of 25% Phosphoric Acid.
75% Phosphoric Acid is 12.0848 Molar
25% Phosphoric Acid is 2.9241 Molar
60.49 mL x 12.0848 Molar Concentration at 75% = 250 mL x 2.9241 Molar Concentration at 25% = TRUE or FALSE
731 = 731 = TRUE
Looking at this another way, as the proof test:
Density of 75% Phosphoric Acid = 1.5790 g/CC
Density of 25% Phosphoric Acid = 1.1462 g/CC
60.49 mL x 1.579 g/mL x 75% = 71.6353 grams of pure 100% Phosphoric Acid initial
250 mL x 1.1462 g/mL x 25% = 71.6375 grams of pure 100% Phosphoric Acid final
71.64 grams initial = 71.64 grams final = TRUE
The only slight difference in grams computed is attributable to rounding error.
If you start out with a certain weight in grams of pure phosphoric acid, and dilute it to 250 mL, you had best end up with the same number of grams of pure Phosphoric Acid, no? Your method assuredly fails this test miserably as follows:
83 mL x 1.5790 g/mL x 0.75 = 98.293 grams of pure 100% phosphoric Acid
250 mL x 1.1462 g/mL x 0.25 = 71.6375 grams of pure 100% Phosphoric Acid
98.293 grams initial = 71.64 grams final = FALSE
Your method fails to account for the density changes involved in dilution.