Killick Greenie
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- Mar 18, 2010
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Morning. I'm doing AG7 today (Witches Brew) and I'm going to have a go a water treatment. I've been using campden tablets up to now and having spent a few hours reading up on expert opinion on this forum I went out and bought a salifert kit.
I've read up on everything I could find but the bit that has me confused is the conversion from meq/l to CACO3.
I understand that you take the meq/l reading from the chart in the salifert kit and multiply it by 50 to get a number for the CACO3 :wha: But what are the units of CACO3? PPM? mg/l?
I just need to know the number and units of the CACO3 figure that I should be plugging in to the water treatment calculator.
BTW, this brew is going into my nice new shiny corny kegs as supplied by Norm :thumb: I'm also being drawn to the idea of building a kegerator, is this normal? This all started off with a woodfords wherry kit, was there something in it that dragged me into the dark side of AG brewing? :shock:
Thanks
PS Just done the test and had to use low resolution mode to get a reading of 4.32 meq/l so multiply by 50 = 216 but 216 what :wha:
The water company report say's the alkalinity in this area is 293 mg/l so I assume my figure of 216 will equate to mg/l ?
I've read up on everything I could find but the bit that has me confused is the conversion from meq/l to CACO3.
I understand that you take the meq/l reading from the chart in the salifert kit and multiply it by 50 to get a number for the CACO3 :wha: But what are the units of CACO3? PPM? mg/l?
I just need to know the number and units of the CACO3 figure that I should be plugging in to the water treatment calculator.
BTW, this brew is going into my nice new shiny corny kegs as supplied by Norm :thumb: I'm also being drawn to the idea of building a kegerator, is this normal? This all started off with a woodfords wherry kit, was there something in it that dragged me into the dark side of AG brewing? :shock:
Thanks
PS Just done the test and had to use low resolution mode to get a reading of 4.32 meq/l so multiply by 50 = 216 but 216 what :wha:
The water company report say's the alkalinity in this area is 293 mg/l so I assume my figure of 216 will equate to mg/l ?