steve123
Well-Known Member
I’m looking to brew 2 La Chouffe clone’s. I have a 70L boil kettle and an old 35 litre boil kettle that just needs an element adding (which I have a spare one). I’m going to do one mash (60 L mash tun), and split the wort into 2 kettles.
I aim to get 38L out of the larger BK and 19 L out of the smaller to go into the fermenter.
I want to do the larger with about a OG of 1.073 and the smaller as 1.05.
I’m aiming for an efficiency of 85%, using brewers friend if I aimed for OG of 1.073 at 38L I would use 10 KG grain and 1/2 Kg sugar, for OG of 1.05 at 19L is says use 3.4 KG grain and 0.18 KG sugar.
So adding these figures together I would use 13.4 kg grain with 0.68 KG grain, using a mash thickness of 2.5 L water per KG grain, this would be 33.5 L water with a water absorption rate of about 13 1/2 kg, giving 20 L wort from mash plus sparge .
My question being how do I split the quantities, from the 20L mash how much do I add to each BK then how do I split the sparge?
I aim to get 38L out of the larger BK and 19 L out of the smaller to go into the fermenter.
I want to do the larger with about a OG of 1.073 and the smaller as 1.05.
I’m aiming for an efficiency of 85%, using brewers friend if I aimed for OG of 1.073 at 38L I would use 10 KG grain and 1/2 Kg sugar, for OG of 1.05 at 19L is says use 3.4 KG grain and 0.18 KG sugar.
So adding these figures together I would use 13.4 kg grain with 0.68 KG grain, using a mash thickness of 2.5 L water per KG grain, this would be 33.5 L water with a water absorption rate of about 13 1/2 kg, giving 20 L wort from mash plus sparge .
My question being how do I split the quantities, from the 20L mash how much do I add to each BK then how do I split the sparge?